MDwiki gimmick test

Alert

Warning: This text is important.

Note! This is a note.

Hint: This is a hint.

\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

Diameter \( d \) of a circle given area \( A \) can by obtained via \(d=\sqrt{\frac{4A}{\pi}}\)